首页
附加题:(1)方程x2=1的解为______.(2)计算:=______
试题详情
附加题:
(1)方程x
2=1的解为______.
(2)计算:
![](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAACYAAAASCAYAAAA31qwVAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
jwv8YQUAAAAJcEhZcwAADsMAAA7DAcdvqGQAAAFMSURBVEhL7ZU9EoQgDIVzLgqOY89NrDmIrQex
4ChZAqIgQcK6dsuMM47C88vLj4DMAgCUXNzZ3jOJbtjTAut94Nv39FHJ+oMll37rmLOoU92ZVZKJ
5h4OzFl91rS26PxpQSpXNPtmRH/vAZ+w1WC5/hlPH8y5EEFaq8nBHFqt0eYbgrvGh8CvCmw1bKB9
sFzfi0BlVwbXgSKpEozOptFUBiMGI6fCfGHzGFMMN071ij/qn+6LwYLw3gS6yB29eA4W5X0T7IGP
gaXDRzMkqJQGAmzXV53Kax2ejQC4THurTseu21lT1BnVyBUk67JRbXI+ObYsSwCaFaCat3DfBovF
Kh0XY9q+IAxXYyG66FoBRg5lP3UpVJGklnY+uC/zsaixyb8k16S/jcaoYh+Pahdg26wQ1PwK2Kh2
1ZUU2RuOkY0j2sPjYiR93F5p0B9F4VRsthWfHAAAAABJRU5ErkJggg==
)
=______
相关试题
-
附加题:
(1)方程x2=1的解为______.
(2)计算:
=______
-
附加题:计算:3y+x2-3y+2x2=________.
-
附加题.(1)方程2x-6=0的解为______.(2)计算:a2•a3•a=______.
-
附加题:已知x1,x2是方程x2-x-3=0的两个根,求x12+x22的值.
【解析】
根据根与系数的关系得x1+x2=1,x1-x2=-3
∴x12+x22=(x1+x2)2-2x1x2=12-2×(-3)=7.
请根据解题过程中体现的数学方法解决下面的问题:
已知:△ABC的两边AB、AC的长是关于x的方程x2-(2k+3)x+k2+3k+2=0的两个实数根,第三边BC的长为5.试问:k取何值时,△ABC是以BC为斜边的直角三角形?
-
(2009•泉州质检)附加题
(1)如图,直线a,b被址线c所截,若a∥b,且∠1=60°,则∠2=______度.
(2)方程x2=1的解是______.
-
附加题:
(1)一元二次方程x2-1=0的解为______.
(2)已知△ABC∽△A′B′C′,∠A=50°,则∠A的对应角∠A′=______度.
-
计算和解方程
(1)计算
+(-5)2-(
-
).(2)
.
(3)解方程x2-4x+3=0 (4)解方程x2+4x-1=0.
-
小东在用计算器估算一元二次方程x2-3x+1=0的近似解时,对代数式x2-3x+1进行了代值计算,并列成下表.由此可以判断,一元二次方程x2-3x+1=0的一个解x的范围是( )
x | -1 | -0.5 | | 0.5 | 1 |
x2-3x+1 | 5 | 2.75 | 1 | -0.25 | -1 |
A.-1<x<-0.5
B.-0.5<x<0
C.0<x<0.5
D.0.5<x<1
-
(1)计算(2
![](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAFkAAAASCAYAAAAwlHIAAAAAAXNSR0IArs4c6QAAAARnQU1BAACx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)
(2)![](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAHMAAAAlCAYAAABxlNYMAAAAAXNSR0IArs4c6QAAAARnQU1BAACx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)
(3)解方程:4x2=9
(4)解方程:x2-6x+1=0.
(5)计算(
)-1-2010+
-
.
-
解方程或计算
(1)计算:![](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAL8AAAAZCAYAAABgr//1AAAAAXNSR0IArs4c6QAAAARnQU1BAACx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==
)
(2)解方程:x2-4x-5=0.