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已知函数,数列an满足a1=1,an+1=f(an)(n∈N*).(1)求数列{an}的通...
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已知函数
,数列a
n满足a
1=1,a
n+1=f(a
n)(n∈N
*).
(1)求数列{a
n}的通项公式;
(2)记S
n=a
1a
2+a
2a
3+…+a
na
n+1,求S
n.
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